Question #74381

Calculate the root mean square velocity, in m/s, of fluorine molecules (F2) at 22oC

Expert's answer

Molar mass M(F2) = 0.038 kg/mol

T = 273 + 22 = 295 K

m0×v2/2=(3×k×T)/2

k = 1.38×10-23 J⋅K−1

m0=M(F2)/Na

Na = 6.02×1023 mol-1

Then v2 = (3×k×T×Na)/M(F2)

v2 = (3×1.38×10-23x295×6.02×1023)/0.038 = 193480

v = √193480 = 439.8 m/s

T = 273 + 22 = 295 K

m0×v2/2=(3×k×T)/2

k = 1.38×10-23 J⋅K−1

m0=M(F2)/Na

Na = 6.02×1023 mol-1

Then v2 = (3×k×T×Na)/M(F2)

v2 = (3×1.38×10-23x295×6.02×1023)/0.038 = 193480

v = √193480 = 439.8 m/s

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