Answer to Question #67891 in Inorganic Chemistry for marcella mwenibabu

Question #67891
What weight of silver nitrate is required to prepare 300mL of 0.1 ppm silver (Ag+)
1
Expert's answer
2017-05-01T09:51:08-0400
Dissociation of silver nitrate in solution:
AgNO3 ↔ Ag+ + NO3-
This means that the mol number of silver nitrate is the same for silver
n(AgNO3)=n(Ag+)
c(AgNO3)=n(AgNO3)V
n(Ag+)=n(AgNO3)=c(AgNO3)∙V
Ppm to mol/L:
ppm of silver nitrate is 5.9·10-7 mol/L
n(AgNO3)=5.9∙10-7molL∙0.3 L=1.77∙10-7mol
The mass of silver nitrate is:
m(AgNO3)=n(AgNO3)∙M(AgNO3)
m(AgNO3)=1.77∙10-7mol ∙169.87gmol=3.0∙10-5g

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