What weight of silver nitrate is required to prepare 300mL of 0.1 ppm silver (Ag+)
Dissociation of silver nitrate in solution: AgNO3 ↔ Ag+ + NO3- This means that the mol number of silver nitrate is the same for silver n(AgNO3)=n(Ag+) c(AgNO3)=n(AgNO3)V n(Ag+)=n(AgNO3)=c(AgNO3)∙V Ppm to mol/L: ppm of silver nitrate is 5.9·10-7 mol/L n(AgNO3)=5.9∙10-7molL∙0.3 L=1.77∙10-7mol The mass of silver nitrate is: m(AgNO3)=n(AgNO3)∙M(AgNO3) m(AgNO3)=1.77∙10-7mol ∙169.87gmol=3.0∙10-5g
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