# Answer to Question #4432 in Inorganic Chemistry for Victor

Question #4432

break the following equations into two half equation.One for oxidation and one for reduction. 2cl(g)+2I(aq)=2cl(aq)+I2(aq)

Expert's answer

Correctly, this equation can be written as:

Сl2(g)+2I-(aq)=2Сl-(aq)+I2(aq)

Oxidation: Сl2(g)→2Сl-(aq) +2e-

Reduction: 2I-(aq) +2e- →I2(aq)

Сl2(g)+2I-(aq)=2Сl-(aq)+I2(aq)

Oxidation: Сl2(g)→2Сl-(aq) +2e-

Reduction: 2I-(aq) +2e- →I2(aq)

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