I want to accurately finished solution with precise octane values. What are the equations required to accomplish this task. For example, 1 solvent is 155 octane the other, 94. I want to finish off with 116 octane in a 205 quantity.
1
Expert's answer
2013-02-05T10:32:35-0500
Derive a formula for a start: octane value = octane value1*(% component1) + octane value2*(% component2) octane value1 = 94 octane value2 = 155 % component1 = x % component2 = 1-x octane value = 116
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult.
You can find this expert in "Assignmentexpert.com" with confidence.
Exceptional experts! I appreciate your help. God bless you!
Comments
Leave a comment