Answer to Question #22096 in Inorganic Chemistry for khadijah
b. What is the mass of water produced?
2H2 + O2 = 2H2O
n(H2) = m/M
n(H2) = 15g/2g/mol = 7,5 mol
n(O2) = 48g/32g/mol = 1,5 mol
a. The limiting reagent is O2
n(H2O) =1,5 mol
M(H2O) = 2*1 + 16 = 18 g/mol
m(H2O) = 18g*1,5 mol = 27g
b.The mass of water produced is 27g.
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