Answer to Question #20183 in Inorganic Chemistry for rana
L*m(ice) = c*t*m(water)
where L = 335 kJ/kg is specific heat of melting for ice andc = 4200 J/(kg*K) is specific heat capacity.
m(ice) = c*t*m(water)/L = 4200*15*0.15/(335*10^(3)) = 0.0282kg = 28.2 g
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