Looking at equation B, what will happen to the reaction rate if pressure is decreased in the reaction vessel?
2 SO2(g) + O2(g) --> 2 SO3(g)
b. stays the same
there is a decrease in pressure than the equilibrium will shift towards the side of the reaction with more moles of gas.
That is backward , this means that the
Rate of reaction decrease.
Option (a. )decreases