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Answer to Question #18238 in Inorganic Chemistry for sean

Question #18238
calculate the mass of butane needed to produce 53.9 grams of carbon dioxide
Expert's answer
2C4H10+ 13O2 = 8CO2 + 10H2O;
n(CO2) = 53.9g/44 g/mol
n(CO2) = 1.225 mol;
n(C4H10) = 0.30625 mol;
m(C4H10) = 0.30625 mol * 58 g/mol = 17.7625 g

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