Answer to Question #179609 in Inorganic Chemistry for Alex

Question #179609

______C2H6  +  ______O2  -->  ______CO2  +  _______H2O


Calculate the mass of carbon dioxide formed when 7.80 g of benzene (C2H6) burns.


1
Expert's answer
2021-04-11T23:50:58-0400

2C2H6 + 7O2 -------> 4CO2 + 6H2O


2C6H6 + 15O2 -------> 12CO2 + 6H2O

(Formula for benzene is C6H6, we shall therefore work with the second equation)


Molar mass of benzene = 78 g/mol

Moles of benzene = 7.8 g/78 g/mol = 0.1 moles

From the balanced equation above, 2 moles of benzene burn in O2 to form 12 moles of CO2

Therefore, 0.1 moles of benzene burns in O2 to form (12/2) x 0.1 = 0.6 moles of CO2

Molar mass of CO2 = 44 g/mol

Hence, mass of CO2 formed = 0.6 moles x 44 g/mol = 26.4 g



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