Answer to Question #154781 in Inorganic Chemistry for mary

Question #154781

What's the formal charge of the central atoms in Carbamylcholine?


1
Expert's answer
2021-01-12T07:00:23-0500

Carbamylcholine =


The structure of Carbamylcholine (also called Carbachol) is;



Formal charge = [number of valence electrons] – [electrons in lone pairs + 1/2 the number of bonding electrons]


but the above formula can be simplified for easier calculation to;

Formal Charge = [number of valence electrons] – [non-bonded electrons + number of bonds]


-> The first central atom is Nitrogen.

number of valence electrons = 5

number of bonds around Nitrogen = 4

number of non-bonded electrons = 0


Formal Charge = 5 – [4+0] = 1



-> The second central atom is Carbon

number of valence electrons = 4

number of bonds around Carbon = 4

number of non-bonded electrons = 0


Formal Charge = 4 – [4+0] = 0



-> The third central atom is another Carbon

number of valence electrons = 4

number of bonds around Carbon = 4

number of non-bonded electrons = 0


Formal Charge = 4 – [4+0] = 0



-> The fourth central atom is Oxygen

number of valence electrons = 6

number of bonds around Oxygen = 2

number of non-bonded electrons = 4


Formal Charge = 6 – [2+4] = 0



-> The fifth central atom is Carbon

number of valence electrons = 4

number of bonds around Carbon = 4

number of non-bonded electrons = 0


Formal Charge = 4 – [4+0] = 0



-> The sixth central atom is Nitrogen

number of valence electrons = 5

number of bonds around Nitrogen = 3

number of non-bonded electrons = 2


Formal Charge = 5 – [3+2] = 0


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