101 494
Assignments Done
99.6%
Successfully Done
In September 2021

# Answer to Question #140934 in Inorganic Chemistry for Nor-Hannah Amiril

Question #140934
A closed system initially containing 1.000 × 10-3 M H2 and 2.000 × 10-3 M I2 at 448℃ is allowed to reach equilibrium. At equilibrium, the HI concentration is 1.87 × 10-3 M. Given that the reaction equation is H2(g) + I2(g) ↔ 2 HI(g), find:
a. Equilibrium concentrations of the two reactants
b. Kc of the reaction taking place.
1
2020-10-29T05:24:06-0400

### Solution:

Chemical reaction:

H2(g) + I2(g) ↔ 2HI(g)

Given:

[H]in = 10-3M

[I]in = 2*10-3M

[HI]eq = 1.87*10-3M

this problem is solved by using ICE table method:

Firstly we should find x(change) in the ICE table:

2x=1.87*10-3

x=9.35*10-4

a) Equilibrium concentrations of the two reactants:

[H]eq = 10-3 - 9.35*10-4 = 6.5 * 10-5 M

[I]eq = 2*10-3 - 9.35*10-4 = 1.065 * 10-3 M

b) Kc of the reaction taking place:

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!