Answer to Question #94321 in General Chemistry for namasiku
The first year student in the school of health sciences was asked to prepare 250cm3 of 0.1mol/dm3 sodium carbonate solution. The student weighed 2.65g of sodium carbonate decahydrate, (Na2CO3.10H2O), instead of anhydrous sodium carbonate (Na2CO3). Calculate the concentration of the solution prepared by the student in mol/dm3
MNa2CO3x10H2O = 286 g/mol
CNa2CO3= = m/(MNa2CO3x10H2O* V) = 2.65/(286*0.25) = 0.037 mol/dm^3
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