Answer to Question #86410 in General Chemistry for taha
A 1.79 g sample of an unknown gas has a volume of 530 mL and a pressure of 923 mm Hg at 36.6 °C. Calculate the molar mass of this compound.
m(gas) = 1.79 g
V(gas) = 530 ml = 0.00053 m3
p(gas) = 923 mm Hg = 123056.5 Pa
T = 36.6°C = 309.6 K
R = 8.31 J⋅mol−1⋅K−1
Solution:@$p*V = (m*R*T)/M@$@$M = (m*R*T)/ (p*V)@$
M(gas) = (1.79 g*8.31 J⋅mol−1⋅K−1*309.6 K) / (123056.5 Pa*0.00053 m3) = 70.61 g/mol
The molar mass of this compound is 70.61 g/mol.
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