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Answer to Question #58269 in General Chemistry for sara

Question #58269
If 0.106 moles of zinc reacts with excess lead(IV) sulfate, how many grams of zinc sulfate would be produced?
Expert's answer
2Zn + Pb(SO4)2 = 2ZnSO4 + Pb
N(ZnSO4)=N(Zn)= 0.106 moles.
m(ZnSO4)=0.106* 161.45=17.11g

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