A 2.50 g sugar cube (sucrose: C12H22O11) is dissolved in a 350 mL teapot containing 80∘ C water (density of water at 80∘ C= 0.975 g/mL). What is the molality of the sugar solution?
Express the molality with the appropriate units.
I entered these and they are not correct, can you help?
ANSWER 1: Deduction: -3%
0.03molkg
ANSWER 2: Deduction: -3%
343.77gmol
Enter your answer using dimensions of concentration.
1
Expert's answer
2015-11-05T12:43:54-0500
b = n (of solute) / m (of solvent) solvent – H2O solute – C12H22O11 ρ (density) = m / V (mass / volume), so m = ρ * V m (H2O) = 0.975 (g/mL) * 350 mL = 341.25 g n = m / M n (C12H22O11) = 2.5 g / 342 g/mol = 0.0073 mol b (solution) = 0.0073 mol / 0.3413 g = 0.021 mol/kg Answer: 0.021 mol/kg
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
Leave a comment