Now consider a situation in which 26.0 g of P4 is added to 59.0 g of Cl2, and a chemical reaction occurs. To identify the limiting reactant, you will need to perform two separate calculations:
1.Calculate the number of moles of PCl5 that can be produced from 26.0 g of P4 (and excess Cl2).
2.Calculate the number of moles of PCl5 that can be produced from 59.0 g of Cl2 (and excess P4).
Then, compare the two values. The reactant that produces the smaller amount of product is the limiting reactant.**answer to #1 is 0.839 moles...answer to #2 is 0.333 moles
Info needed:What mass of PCl5 will be produced from the given masses of both reactants?
Express your answer to three significant figures and include the appropriate units.