Answer to Question #55696 in General Chemistry for sue
m(H2O) = ???? Thank you!
n(H2) = 10.4/2 = 5.2 (mol) – excess
m(H2O) = n*M = 3*n(Fe2O3) * M(H2O) = 3*0.1056*(16+1*2) = 5.7024 (g)
m(H2O) = 5.7024 g
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