Question #55658

Nitrogen gas reacts with hydrogen gas to produce ammonia.
N2(g)+3H2(g)→2NH3(g)
How many grams of H2 are needed to react with 3.40 g of N2?
Thanks for your help!!

Expert's answer

The balanced chemical eqiation is

N_{2}(g)+3H_{2}(g)→2NH_{3}(g)

The mass of nitrogen is m(N_{2}) = 3.40 g

The amount of nitrogen is n(N_{2}) = m(N_{2})/M(N_{2[]/sub) = 3.4/28.013 = 0.121 molThe reacion stechiometry shows that we need 3 times more moles of hydrogen to react completely with this amount of nitrogen, or n(H[sub]2}) = 3x0.121 = 0.363 mol

The mass of hydrogen reqired is m(H_{2}) = n(H_{2})M(H_{2}) = 0.363x2.016 = 0.732 g

Answer: 0.732 g

N

The mass of nitrogen is m(N

The amount of nitrogen is n(N

The mass of hydrogen reqired is m(H

Answer: 0.732 g

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