# Answer to Question #55656 in General Chemistry for Misha Jain

Question #55656

Find the minimum and maximum value of (n+l+m) in first excited state of unpaired electron (last) of Cl.

Expert's answer

The electronic configuration of chlorine ground state is

1s

The electronic configuration of chlorine first excited state is

1s

So, this electron is on 4s orbital and can be characterized by the following quantum numbers:

n = 4

l = 0

m = 0

The minimum and maximum value of (n+l+m) coinciding and equals to 4

Answer: 4

1s

^{2}2s^{2}2p^{6}3s^{2}3p^{5}The electronic configuration of chlorine first excited state is

1s

^{2}2s^{2}2p^{6}3s^{2}3p^{4}4s^{1}So, this electron is on 4s orbital and can be characterized by the following quantum numbers:

n = 4

l = 0

m = 0

The minimum and maximum value of (n+l+m) coinciding and equals to 4

Answer: 4

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