Find the minimum and maximum value of (n+l+m) in first excited state of unpaired electron (last) of Cl.
1
Expert's answer
2015-10-20T03:49:18-0400
The electronic configuration of chlorine ground state is 1s22s22p63s23p5 The electronic configuration of chlorine first excited state is 1s22s22p63s23p44s1 So, this electron is on 4s orbital and can be characterized by the following quantum numbers: n = 4 l = 0 m = 0 The minimum and maximum value of (n+l+m) coinciding and equals to 4 Answer: 4
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