Question #55656

Find the minimum and maximum value of (n+l+m) in first excited state of unpaired electron (last) of Cl.

Expert's answer

The electronic configuration of chlorine ground state is

1s^{2}2s^{2}2p^{6}3s^{2}3p^{5}

The electronic configuration of chlorine first excited state is

1s^{2}2s^{2}2p^{6}3s^{2}3p^{4}4s^{1}

So, this electron is on 4s orbital and can be characterized by the following quantum numbers:

n = 4

l = 0

m = 0

The minimum and maximum value of (n+l+m) coinciding and equals to 4

Answer: 4

1s

The electronic configuration of chlorine first excited state is

1s

So, this electron is on 4s orbital and can be characterized by the following quantum numbers:

n = 4

l = 0

m = 0

The minimum and maximum value of (n+l+m) coinciding and equals to 4

Answer: 4

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