A room contains 48 kg of air. How many KWh of energy are necessary to heat the air in the house from 7oC to 28oC? The heat capacity of air is 1.03 J/goC.
1
Expert's answer
2015-10-19T05:09:41-0400
Q = C*m*(T2 - T1) = 1.03 J/(g*K)*48 kg*(28 C - 7 C) = 1.03 J/(g*K)*48000 g*(28 C - 7 C) = 1038240 J = 288.4 Wh = 0.2884 kWh
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
Dear visitor, please use panel for submitting new questions
At what velocity (m/s) must a 28.7 kg object be moving in order to possess a kinetic energy of 1.03 J?
Leave a comment