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# Answer to Question #55391 in General Chemistry for tracy Guido

Question #55391
NaHCO3(aq) + H3C6H5O7(aq) = H2O(l) + CO2(g) + NaC6H5O7(aq)
9 NaHCO3(aq) + 8 H3C6H5O7(aq) = 14 H2O(l) + 3 CO2(g) + 9 NaC6H5O7(aq)

List at least 2 types of reactions that the equation in question #2 can be categorized as?
If 0.950 grams of citric acid (C6H8O7) reacts
How many moles of sodium bicarbonate will be consumed
How many moles of carbon dioxide will be generated
How many grams of carbon dioxide will be generated

One type of reaction is combustion What would be the second?

Convert grams to moles
.950 g citric acid x (1 mole/ 192.123 grams C6H8O7) = .005 moles of C6H8O7

how many moles of sodium bicarbonate will be consumed
.005 moles of C6H8O7 x (9 moles NaHCO3/1 mole of C6H8O7) = .045 moles of NaHCO3

how many moles of carbon dioxide will be generated
.005 moles of C6H8O7 x (14 moles H2O/1 mole of C6H8O7) = .07 moles of H2O

how many grams of carbon dioxide will be generated
.07 moles of H2O x (18.015 grams of H2O/1mole H2O) = 1.261 grams of H2O

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