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Answer to Question #53064 in General Chemistry for thevoice

Question #53064
By use of the following data at 25°C, solubility product(Ksp) of AgBr 4.88*10^-13 standard electrode potential: E(Ag/Ag)=0 .799 E(Br2(liquid)/Br) =1.065 V(1) Calculate the standard electrode potential for AgBr(s)/Ag at 25°C
(2) Design a cell for calculation of the standard Gibbs Energy formation of AgBr(s).
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