Question #229613

a graduated cylinder contains 20.5ml of water. what is the new water level after 41.3g of silver metal with a density of 10.5g/cm3 is submerged in the water

Expert's answer

The increase in water level must equal the volume of the submerged silver.

ΔV = volume of silver

"\u0394V = \\frac{m}{\u03c1 }=\\frac {(41.6 g)}{(10.5 g\/mL) }=3.96 mL"

V = final water level

"V = (25.0 + 3.96) mL=28.96 mL"

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