Answer to Question #229613 in General Chemistry for Talla Fall

Question #229613

a graduated cylinder contains 20.5ml of water. what is the new water level after 41.3g of silver metal with a density of 10.5g/cm3 is submerged in the water


1
Expert's answer
2021-08-26T01:08:31-0400

The increase in water level must equal the volume of the submerged silver.

 

ΔV = volume of silver

 

"\u0394V = \\frac{m}{\u03c1 }=\\frac {(41.6 g)}{(10.5 g\/mL) }=3.96 mL"


V = final water level

 

"V = (25.0 + 3.96) mL=28.96 mL"


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