Answer to Question #229387 in General Chemistry for MOU

Question #229387

Prepare a solution of 1M iodine in 250mls of water. Molar 126.2g/mol


1
Expert's answer
2021-08-25T06:36:43-0400

M(I2) = 252.4 g/mol

Proportion for 1 M solution:

1 L – 252.4 g

0.250 L – x g

"x = \\frac{0.250 \\times 252.4}{1} = 63.1 \\; g"

You need 63.1 g of I2, but in real laboratory practice I2 will not dissolve in pure water without KI.


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