Question #218434

hydrochloric acid is given below.

M2CO3 + 2HCl 2MCl + CO2 + H2O

0.245g of M2CO3 was found to exactly neutralise 23.6cm3 of hydrochloric acid of concentration

of 0.150moldm-3. Carry out the following calculations and hence deduce the identity of M.

i. Calculate the number of moles of hydrochloric acid. [2 marks]

ii. Calculate the number of moles of M2CO3. [2 marks]

iii. Calculate the relative molecular mass of M2CO3. [2 marks]

iv. Calculate the relative atomic mass of the metal M and hence deduce its identity. [

Expert's answer

Moles of "M_2CO_3=\\frac{0.245}{60.008} =0.0041moles"

"M_2CO_3 + 2HCl ===>2MCl + CO_2 + H_2O"

"Moles = 0.0041\u00d72=0.0082" moles

Relative molecular mass of M2CO3

107.2 g/mol

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