Answer to Question #218315 in General Chemistry for Ma Corazon Partosa

Question #218315

If 50 g of aluminum nitrite is reacted with 50g of ammonium chloride, how many grams of aluminum chloride will be produced?



1
Expert's answer
2021-07-18T01:28:01-0400

Balanced equation: Al(NO2)3(aq) + 3 NH4Cl(aq) → AlCl3(aq) + 3 N2(g) + 6 H2O(l)

mole ratio between Aluminum nitrite : aluminum chloride = 1:1

50/212.996

Ratio between ammonium chloride: aluminum chloride = 3:1

50/53.491

Molar Mass of aluminum nitrite = 212.996

Molar Mass of ammonium chloride = 53.491

Molar Mass of aluminum chloride = 133.34

= 31.3+41.56

= 72.86g


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