Answer to Question #215205 in General Chemistry for Liana

Question

Carbon disulfide is produced by the reaction of carbon and sulfur dioxide. What is the percent yield of carbon disulfide if the reaction of 180.0 g of sulfur dioxide produces 72.0 grams of carbon disulfide? (3 pts.)

                               5C  +  2SO₂ --> CS₂  + 4CO

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Answer 1

Moles of SO2 reacted = mass / molar mass

= 32.0/ 64.0

= 0.5 mol

2 moles of SO2 forms 1 mol of CS2

so,

theoretical moles of CS2 = 0.5/2 = 0.25 mol

theroetical mass of CS2 = number of mol ×molar mass

= 0.25 mol ×76.1 g/mol

= 19.0 g

actual mass = 10.2 g

percentage yield = actual mass × 100 / theroetical mass

= 10.2*100 / 19.0

=53.7 %

Answer: 53.7 %