Answer to Question #212739 in General Chemistry for Greg

Question #212739

Consider the reaction:

2NO(g)+Br2(g)⇌2NOBr(g) Kp=28.4 at 298 K

In a reaction mixture at equilibrium, the partial pressure of NO is 107 torr and that of Br2

is 122 torr. What is the partial pressure of NOBr in this mixture?


1
Expert's answer
2021-07-05T01:33:29-0400

the partial pressure of NO is 107 torr and that of Br2

is 122 torr

"Kp= {products}\/{reactants}"

28.42= PNOBR/1072+1222

PNOBr= 80torr




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