Answer to Question #205400 in General Chemistry for Isolomuzi

Question #205400

2.In a redox reaction



Fe 2 O 3 + KNO 3 + KOH = K 2 FeO 4 + KNO 2 + H 2 O


find an oxidizing agent and a reducing agent, arrange the coefficients by any method (electronic or ion-electronic balance).


1
Expert's answer
2021-06-11T01:58:07-0400

Now the oxidation number of Fe in reactant side is +3 but it increases to +6 on the product side so it oxidized hence it will behave as a Reducing agent.


The oxidation number of K in reactant side is +3 but it decreases to +1 on the product side so it reduced hence it will behave as a Oxidizing agent.


The balance chemical equation of the above is:






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