Answer to Question #204479 in General Chemistry for stevie

Question #204479

Calculate the number of grams of bromine (Br2) needed to react exactly with 50.1 g aluminium (Al). The equation for the reaction is:

2Al (s) + 3Br2 (l) → 2AlBr3 (s)

Then, calculate the number of moles of AlBr3 produced by the process.


1
Expert's answer
2021-06-09T03:11:02-0400

As per the chemical equation

2 moles of Aluminum react with 3 moles of Bromine to generate 2 moles of Aluminum Bromide

 

Molecular Weight of Al= 27 g/mol

Molecular Weight of Bromine= 159.8 g/mol

Molecular Weight of Aluminum Bromide= 266.7 g/mol

 

Moles of Al "=\\frac{50.1}{27}=1.85 moles"


Moles of Br2"=\\frac {3}{2}\u00d71.85=2.775moles"


Mass of Br2 "=2.775\u00d7159.8=443.45grams"


Moles of AlBr3"= 1.85"



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