Question #204474

Ruthenium-106 has a half-life of 1.0 years. How many half-lives will pass in 25 years?

Expert's answer

At very first assume that the solution is of "1l"

Now:

Comparing the "K_a" of acetic acid, "1.76X10^-5" , these solutions aren’t very large comparative to .25M and .1M, it’s a buffer equation because there is a acid and conjugate base, so you’re able to use the Henderson Hasselbalch equation.

Now :

"P_H= P_{Ka} + log (\\dfrac{base}{acid})"

"P_H= 4.76 + log(\\dfrac{0.1}{0.25})"

"P_H=4.362"

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