Mark is measuring the specific heat of a new type of coolant he first warms 75.0 g of this coolant from 23.5*C to 45.0*C then he puts the warm coolant into a calorimeter and cools it back to 23.5 *C the calorimeter calculations show the sample coolant shed 1370 calories of energy. What is the specific heat of the coolant?
Q= 1370 cal
ΔT = 45.0-23.5=21.5
Q = mCΔT
The specific heat of the coolant is 0.849 cal/gC