Question #195002

A teacher needs to make 120.0 mL of a 4.00 M HCl solution using a stock solution with a concentration of 12.0 M. Determine the volume of 12.0 M HCl needed to make the dilution.

Expert's answer

c_{1} = 12.0 M

V_{1} = unknown

c_{2} = 4.00 M

V_{2} = 120.0 mL

**Solution:**

The equation for dilution calculations can be used.

where:

c_{1}, V_{1} - the molarity and volume of the concentrated solution

c_{2}, V_{2} - the molarity and volume of the diluted solution

Thus:

(12.0 M) × V_{1} = (4.00 M) × (120.0 mL)

V_{1} = (4.00 M × 120.0 mL) / (12.0 M) = 40 mL

**V**_{1}** = 40 mL**

**Answer: 40 mL of 12.0 M HCl needed to make the dilution.**

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