C. Calculate the grams of lead (II) iodide that can be reproduced from 75.00 grams of potassium iodide
75.00 g of KI = 75.00 / 166 = 0.452 moles
0.45 moles of KI produces 0.45 /2 = 0.226 mol PbI2
Amount of PbI2 produced = 0.226 x 461
= 104.1 grams
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
How to Finish Assignments When You Can’t
Crunch time is coming, deadlines need to be met, essays need to be submitted, and tests should be studied for.…
How to Effectively Study for a Math Test
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
Why Am I A Bad Student?
The moment you’ve entered the education system is the moment you start to realize that, although studying is extremely important,…