Answer to Question #190169 in General Chemistry for Emaan

Question #190169

Determine the quantity of energy that will be needed to melt 2.5 X 105 Kg of iron at its melting 

point 1536°C. The enthalpy of fusion of iron is 13.807 kJ/mol.


1
Expert's answer
2021-05-08T23:48:50-0400

2.5 X 10"^{5}" kg = 2.5 X 10"^{8}" g of Fe.

number of moles of Fe= mass of Fe"\/" Atomic weight of Fe= 2.5X10"^{8}\/" 55.85 = 44.76 X 10"^{5}" moles of Fe.

Ethalpy of fusion=13.807 kJmol"^{-1}"

Thus, 1mole requires 13.807kJ energy. Therefore 44.76 X 10"^{5}" moles requires 44.76 X 10"^{5}" X 13.807 kJ = 618 X 10"^{5}" kJ energy.


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