Answer to Question #190150 in General Chemistry for Tyler Drotning

Question #190150

Calculate the moles of potassium sulfide formed when 5.4g of potassium gas reacts with excess sulfur.


2 K+S > K2S


1
Expert's answer
2021-05-08T23:48:46-0400

Ans:-

Reaction :

"2 K+S \\leftrightarrow K_2S"

We have "5.4 g" of Potassium firstly find its mole

mole of potassium"=\\dfrac{5.4}{39}=0.138" mole

from the reaction we clearly seen that

According to stoichiometry "2" mole of potassium formed "1" mole of potassium sulfide.

"2" mole of potassium produced = "1" mole of potassium sulfide

"0.138" mole of potassium formed ="\\dfrac{1}{2}\\times0.138=0.276" mole

"\\therefore" "0.276" moles of potassium sulfide produced by "5.4" gof potassium


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