Answer to Question #190140 in General Chemistry for Nailah

Question #190140

Part A: A hydrochloric acid solution has a pH of 2.8. Calculate the concentration of hydronium and hydroxide ions in the solution.

Part B: A sodium hydroxide solution has a concentration of 7.1 x 10^3. Calculate the pH of the solution.

Part C: The hydrochloric acid and sodium hydroxide react together in neutralization reaction. Write the balanced chemical equation for the reaction. Label the acid, base, and salt.


1
Expert's answer
2021-05-07T05:26:05-0400

"pH= -log [H3O^+]"


"2.8= [H3O^+]"


"-2.8= log[H3O^+]"


"10^{-2.8} = [H3O^+]"


0.001 = [H3O+]


"1.58\u00d710^{-3}"




"POH = 14-2.8=11.2"






pOH = - log [molarity of OH-] = - log [ molarity of NaOH] , assuming full dissociation.


Thus, pOH = - log ( "7.1\u00d710^{-3}" ) = - (-2.15) = 2.25.

Now, for a solution , pH + pOH = 14

=> pH + 2.25 =14

=> pH = 11.75




HCl(aq) + NaOH(aq ) → NaCl (aq)+ H2O(l)






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