Hello, can you please provide the complete solutions of these questions. The answers are already given.
3. A sample of Al2(SO4)3 weighing 7.52-g was dissolved in enough water
and diluted to 250.0-mL. 100.0-mL of the dilution was transferred to
another flask, 10.0-mL of 0.050M EDTA, 20-mL of buffer solution, 50-mL of
alcohol and 2.0-mL dithizone TS were added. The resulting solution
required 8.7-mL of 0.031M ZnSO4 to reach the endpoint. (Note: Each mL
of 0.050M EDTA is equivalent to 16.66-mg Al2(SO4)3·18H20). Compute for
the percent purity of the sample.
Molar Mass: Al2(SO4)3·18H2O = 666.5
answer: 2.5% Al2(SO4)3
Molar Mass: "Al_2(SO_4)_3\u00b718H_2O" = 666.5
Percent purity of the sample.2.5% "Al_2(SO_4)_3"