Answer to Question #184234 in General Chemistry for akuma

Question #184234

A reaction that occurs when 23 grams of iron (II) chloride reacts with sodium phosphate forming iron (II) phosphate and sodium chloride. what is the limiting reagent? How much sodium chloride can be formed?


1
Expert's answer
2021-04-23T07:30:24-0400

Balanced Equation

3FeCl2+2Na3PO4"\\implies" Fe3(PO4)2+6NaCl

Limiting reagent is FeCl2

Moles of FeCl2 ="\\frac{23g}{126.751g\/mol}"

=0.1815moles


Mole ratio of:

FeCl2:NaCl

3 : 6

If 3=0.1815moles

"\\therefore" 6=?

"\\frac{6\u00d70.1815}{3}" "=0.363moles"


Molar mass of NaCl is 58.44g/mol

But Mass= 0.363moles×58.44g/mol

=21g

Mass Of Sodium Chloride formed =21g



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