Answer to Question #181214 in General Chemistry for Marcus Snearley

Question #181214

What is the volume of 6.00 M nitric acid that contains 6 302 g of HNO 3 solute (63.02g / m * o * l) ?


1
Expert's answer
2021-04-14T06:10:20-0400

First wee need to find the moles of HNO3 in 6302g


We know that;

Moles "= \\dfrac{mass}{molar mass} = \\dfrac{6302g}{63.02g\/mol}"


= 100mol

We also know that;


Molarity "= \\dfrac{moles}{Volume (L)}"


Therefore;


Volume (L) "=\\dfrac{mol}{Molarity} = \\dfrac{100mol}{6.00mol\/L}"


= 16.667 L

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