Answer to Question #181093 in General Chemistry for Justin

Question #181093

The groundwater sample was analysed. The measured pH of the test water at 25°C had a value, pH = 3.8. The concentration of Zn2+ ions in water was also determined to be 4.132·10-2 mol/L.

Groundwater is in equilibrium with sediment containing MnO2 and ammonia. Calculate the

concentration of NH4+ ions under these conditions.

Standard reduction electrode potentials for reactions:


Zn 2++ 2e →Zn E°= -0.76V

 2MnO 2 + 2NH4+ 2e → Mn2O3 +2NH3+ H2O

 E°= 0.74 V

Write a sum cell reaction.


1
Expert's answer
2021-04-14T06:10:17-0400

concentration of NH4+ ions = "4.132\u00d7 10^{-2}"Mol/L



"Zn ^{2+}+ 2e \u2192Zn" "E\u00b0= -0.76V"



"2MnO_2 + 2NH_4+ 2e \u2192 Mn_2O_3 +2NH_3+ H_2O"

"E\u00b0= 0.74 V"


Sum cell reaction = "0.74 -0.76 =-0.02V"



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