Answer to Question #175053 in General Chemistry for JohnDoe

Question #175053

31-35. One of the steps in producing nitric acid using Oswald process is:

4NH3(g) + 5O2(g) → 4NO(g) + 6H20(I) ∆H = -904kJ

Determine the amount of heat in (kJ) given off per 65.3g of NH3 (17g/mol) used.


1
Expert's answer
2021-03-29T05:16:41-0400

Moles of NH3 = "\\frac{65.3}{17}= 3.841 moles"


Heat (KJ)= heat change/1000 ÷ moles


"\u2206H = \\frac{-904}{1000\u00d73.841}\n\n=-0.235kJ"




Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS