calculate the molar concentration of sodium ions if 2.7g of sodium carbonate is dissolved in 175mL of water
Mass of sodium carbonate= 2.7g
Volume of water= 175ml= 0.175L
Mass conc of Na2CO3= 2.7g/0.175L= 15.43g/dm³
Molar mass of Na2CO3= 106g/mol
Molar concentration= mass concentration/molar mass= 15.43/106= 0.15mol/dm³
Now, it follows that Na2CO3 ionizes as follows
Na2CO3----> 2Na+ + CO3²-
Mopar concentration of Na+= 2(0.15)= 0.30mol/dm³
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