Answer to Question #173653 in General Chemistry for Darui

Question #173653

How would you prepare 100 mL of 0.035M NaCl (aq)? 


1
Expert's answer
2021-03-22T06:39:50-0400

Proportion:

0.035 mol – 1000 mL

x mol – 1000 mL

"x = \\frac{0.035 \\times 100}{1000} = 0.0035 \\;mol"

M(NaCl) = 58.44 g/mol

"m = n \\times M = 0.0035 \\times 58.44 = 0.204 \\;g"

You have to add 0.204 g of solid NaCl to the 100 ml volumetric flask and add water to the mark.


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