Answer to Question #167070 in General Chemistry for Nada

Question #167070

Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq), as described by the chemical equation MnO2(s)+4HCl(aq)⟶MnCl(aq)+2H2O(l)+Cl2(g)

How much MnO2(s) should be added to excess HCl(aq)to obtain 185 mL Cl2(g)at 25 °C and 795 Torr?
















1
Expert's answer
2021-03-01T02:34:47-0500

We first find the number of moles of "Cl_2" to be obtained.

"PV=nRT"

"P=" "795Tore\\times 1atm\\over760 Torr" "=1.046Torr"

"V=0.185L"

"n=x" "Mol"

"R=0.0821Latm\/Kmol(Constant)"

"T=298K"

"n=" "moles=" "PV\\over RT" "=" "(1.046)(0.185)\\over (0.0821)(298)" "=0.00791moles Cl_2"

Moles and grams of "MnO_2" needed from the stoichometry equation are;

"0.00791mol Cl_2" "\\times" "1mol MnO_2\\over 1mol Cl_2" "=0.687gMnO_2"

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