Answer to Question #165702 in General Chemistry for Danaya Perlitz

Question #165702

Could 1 mole of peas fit in a 5m x 8m x 2.5m classroom?


1
Expert's answer
2021-02-23T04:26:07-0500

If you selected a hundred("10^2" ) average size paes,you would find they occupy roughly the volume of 20 "cm^3" .


so according to this :

"\\Rightarrow" 20 "cm^3" volume is covered by the peas = "10^2"

"\\Rightarrow" 1 "cm^3" volume covered by ="\\dfrac{10^2}{20}" = 5 Peas.

Now volume of the given room="5m\\times8m\\times2.5m=100m^3" or "10^8 cm^3"


This volume covered peas ="10^8\\times5" Peas only.


but 1 mol of peas contains "6.022\\times10^{23}" peas which is more than our calculated peas that is"5\\times10^8"


So we can say tha 1 mol peas can not fit in the given room.


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