Answer to Question #350262 in Physics for mlas2

Question #350262


A 4.0-g bullet leaves the muzzle of a rifle with a speed of 340 m/s. What force (assumed constant) is exerted on the bullet while it is traveling down the 0.75-m-long barrel of the rifle?


1
Expert's answer
2022-06-14T08:42:11-0400

Given:

"m=0.004\\:\\rm kg"

"v_0=0,\\quad v=340\\:\\rm m\/s"

"d=0.75\\:\\rm m"


The energy-work theorem says

"\\frac{mv^2}{2}-\\frac{mv_0^2}{2}=Fd"

Thus, the force exerted onj the bullet

"F=\\frac{mv^2}{2d}=\\frac{0.004*340^2}{2*0.75}=310\\:\\rm N"


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