A circular coil of radius 5x10-2m and with 40 turns is carrying a current of 0.25 A. determine the magnetic field of the circular coil at the center.
The magnetic field at the center of circular coil
"B=\\frac{\\mu_0 N I}{2\\pi r}""B=\\frac{4\\pi*10^{-7}*40*0.25}{2\\pi*5*10^{-2}}=4*10^{-5}\\:\\rm T"
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