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Answer to Question #312027 in Mechanics | Relativity for Junior

Question #312027

Calculate the energy stored in elastic material with K=1500NM and applied force at 750N

1
Expert's answer
2022-03-17T13:55:31-0400

Answer


Stored energy

"U=\\frac{kx^2}{2}=\\frac{F^2}{2K}\\\\=\\frac{750*750}{3000}\\\\=187.5J"




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