A box of mass 500kg is druged along a level ground at a speed of 12metres per second.if the force of friction between the box and the floor is 1200newtons .calculate the power developed?
Explanations & Calculations
"\\qquad\\qquad\n\\begin{aligned}\n\\small P&=\\small 1200\\,N\\times12\\,ms^{-1}=14400\\,W\n\\end{aligned}"
Comments
Leave a comment